(√31)^2 (√2)^2 2^2 / 2 * (√31) * √2= 2(√31) / 2√2(√31) = √2 / 2 この問題がなぜそうなるのかわかりません。分かる方、途中の式を教えてください。分子(√31)^2(√2)^22^2=32√3124=2(√31)分母2×(√31)×√2=2√2(√31)Solution x=1√2√3 (1) and y=1√2–√3 (2) Add (1) and (2) (xy x = 3/2, y = 1/2 ⇒ √ 2 √3 = √ 3/2 √ 1/2 Algebra teachers usually want us to rationalize denominators, so you can multiply each radical on the righthand side by √ 2/2 to get √ 2 √3 = (1/2)(√ 6 √ 2) Example 3 √ 2 − √3 Solution This is exactly the same deal as Example 2, so I'll hurry through it
What Is The Value Of The Product 1 1 2 1 1 3 1 1 4 1 1 5 Quora
